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POCreate a new string that will consist of common letters from other two strings
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  1. POCreate a new string that will consist of common letters from other two strings
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    copied!<p>I'm new to C programming. I have a task to do. User inputs two strings. What I need to do is to create a new string that will consist only from common letters of those two given strings. For example: if given:</p> <pre><code>str1 = "ABCDZ" str2 = "ADXYZ" </code></pre> <p>the new string will look like: <code>"ADZ"</code>. I can't make it work. I think there must be a better (more simple) algorithm but I have waisted too much time for this one so I want to complete it .. need your help!</p> <p>what I've done so far is this:</p> <pre><code>char* commonChars (char* str1, char* str2) { char *ptr, *qtr, *arr, *tmp, *ch1, *ch2; int counter = 1; ch1 = str1; ch2 = str2; arr = (char*) malloc ((strlen(str1)+strlen(str2)+1)*(sizeof(char))); //creating dynamic array strcpy(arr, str1); strcat(arr,str2); for (ptr = arr; ptr &lt; arr + strlen(arr); ptr++) { for (qtr = arr; qtr &lt; arr + strlen(arr); qtr++) // count for each char how many times is appears { if (*qtr == *ptr &amp;&amp; qtr != ptr) { counter++; tmp = qtr; } } if (counter &gt; 1) { for (qtr = tmp; *qtr; qtr++) //removing duplicate characters *(qtr) = *(qtr+1); } counter = 1; } sortArray(arr, strlen(arr)); // sorting the string in alphabetical order qtr = arr; for (ptr = arr; ptr &lt; arr + strlen(arr); ptr++, ch1++, ch2++) //checking if a letter appears in both strings and if at least one of them doesn't contain this letter - remove it { for (qtr = ptr; *qtr; qtr++) { if (*qtr != *ch1 || *qtr != *ch2) *qtr = *(qtr+1); } } } </code></pre> <p>Don't know how to finish this code .. i would be thankful for any suggestion!</p>
 

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