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copied!<p>You're severely overthinking this. You've only got four vectors. You can determine the largest vector using 3 comparisons. Just do that:</p> <p><s></p> <pre><code>std::vector<blah>& max = vector1; if (max.size() < vector2.size()) max = vector2; if (max.size() < vector3.size()) max = vector3; if (max.size() < vector4.size()) max = vector4; </code></pre> <p></s></p> <h2>EDIT:</h2> <p>Now with pointers!</p> <p><s>EDIT (280Z28):</p> <p>Now with references! :)</s></p> <h2>EDIT:</h2> <p>The version with references won't work. Pavel Minaev explains it nicely in the comments:</p> <blockquote> <p>That's correct, the code use references. The first line, which declares max, doesn't cause a copy. However, all following lines do cause a copy, because when you write <code>max = vectorN</code>, if max is a reference, it doesn't cause the reference to refer to a different vector (a reference cannot be changed to refer to a different object once initialized). Instead, it is the same as <code>max.operator=(vectorN)</code>, which simply causes <code>vector1</code> to be cleared and replaced by elements contained in <code>vectorN</code>, copying them.</p> </blockquote> <p>The pointer version is likely your best bet: it's quick, low-cost, and simple.</p> <pre><code>std::vector<blah> * max = &vector1; if (max->size() < vector2.size()) max = &vector2; if (max->size() < vector3.size()) max = &vector3; if (max->size() < vector4.size()) max = &vector4; </code></pre>

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