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    copied!<p>You can use Placeholders in PHP. But note, that this is not normal Regex behaviour, its special to PHP.:</p> <p><code>preg_match("/&lt;([^&gt;]+)&gt;(.+)&lt;\/\1&gt;/")</code> (the <code>\1</code> references the outcome of the first match)</p> <p>This will use the first match as condition for the closing match. This matches <code>&lt;a&gt;something&lt;/a&gt;</code> but not <code>&lt;h2&gt;something&lt;/a&gt;</code></p> <p>However in your case you would need to turn the "(" matched within the first group into a ")" - which wont work.</p> <p>Update: replacing <code>(</code> and <code>)</code> to <code>&lt;BRACE&gt;</code> AND <code>&lt;END_BRACE&gt;</code>. Then you can match using <code>/&lt;([^&gt;]+)&gt;(.+)&lt;END_\1&gt;/</code>. Do this for all Required elements you use: <code>()[]{}&lt;&gt;</code> and whatevs.</p> <p><code>(a) is as nice as [f]</code> will become <code>&lt;BRACE&gt;a&lt;END_BRACE&gt; is as nice as &lt;BRACKET&gt;f&lt;END_BRACKET&gt;</code> and the regex will capture both, if you use preg_match_all</p> <pre><code>$returnValue = preg_match_all('/&lt;([^&gt;]+)&gt;(.+)&lt;END_\\1&gt;/', '&lt;BRACE&gt;a&lt;END_BRACE&gt; is as nice as &lt;BRACKET&gt;f&lt;END_BRACKET&gt;', $matches); </code></pre> <p>leads to</p> <pre><code>array ( 0 =&gt; array ( 0 =&gt; '&lt;BRACE&gt;a&lt;END_BRACE&gt;', 1 =&gt; '&lt;BRACKET&gt;f&lt;END_BRACKET&gt;', ), 1 =&gt; array ( 0 =&gt; 'BRACE', 1 =&gt; 'BRACKET', ), 2 =&gt; array ( 0 =&gt; 'a', 1 =&gt; 'f', ), ) </code></pre>
 

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