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POMake JPopupMenu Display with a Certain Bottom Left Coordinate
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copied!<p>Say that I want to make a button in Java in such a way so that when you click on it, a <a href="http://docs.oracle.com/javase/7/docs/api/javax/swing/JPopupMenu.html" rel="nofollow noreferrer">JPopupMenu</a> appears. The relevant code for it appearing is <code>menu.show(button, button.getWidth()/2, button.getHeight()/2);</code>, which makes the JPopupMenu be displayed with its top left corner at the center of the button, as shown below:</p> <p><img src="https://i.stack.imgur.com/hrZi6.png" alt="Current Swing JPopupMenu"></p> <p>However, I would like to have it so that instead the bottom left corner is at the center of the button, somewhat like what iTunes does (there is a button underneath the bottom left corner, which is the same size as the <code>+</code> button to the left of it):</p> <p><img src="https://i.stack.imgur.com/MIxfu.png" alt="enter image description here"></p> <p>I tried to make this happen by getting the height of the JPopupMenu and adding it to the y coordinate that the popup menu is being displayed at, but I found out that the JPopupMenu has a height of 0 before it is visible, which doesn't help me since I'm trying to tell the computer where to make it visible. Also, hardcoding in an offset isn't possible because the number of items in the popup isn't necessarily going to be the same.</p> <p>How can I make it so my JPopupMenu with an unknown height can be displayed so that it's bottom left coordinate matches a given coordinate?</p>

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