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PODistance calculation based on multiple locations (Lat,Lon) including starting/ finishing point
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  1. PODistance calculation based on multiple locations (Lat,Lon) including starting/ finishing point
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    copied!<p>I would like to calculate the total distance of driving beetween multiple locations (loop), including the distance (starting point (garage) - first location sarting point) and (last location finishig point - finishing point (garage)). Example: (Garage + D1) + (D1 + D2) + (D2 + E1) + (E1 + E2) + E2 + Garage)</p> <p>I'm having a problem with the correct looping. Here's my simplified code:</p> <pre><code>&lt;? $driver = 5; $result2 = mysql_query("SELECT * FROM test WHERE id='$driver' LIMIT 1") or die(mysql_error()); while($row2 = mysql_fetch_array( $result2 )) { $lon=$row2['lon']; $lat=$row2['lat']; echo "$lon, $lat"; } $result = mysql_query("SELECT * FROM test1 WHERE driver='$driver'") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { $lon1=$row['lon1']; $lat1=$row['lat1']; $lon2=$row['lon2']; $lat2=$row['lat2']; ////////// distance between driver address and starting address $distancecalc = (3958*3.1415926*sqrt(($lat-$lat1)*($lat-$lat1) + cos($lat/57.29578)*cos($lat1/57.29578)*($lon-$lon1)*($lon-$lon1))/180); ////////// distance between statring address and finishing address - multiple adsresses $distancecalc1 = $distancecalc1 + (3958*3.1415926*sqrt(($lat2-$lat1)*($lat2-$lat1) + cos($lat2/57.29578)*cos($lat1/57.29578)*($lon2-$lon1)*($lon2-$lon1))/180); ////////// distance between finishing address and driver address $distancecalc2 = (3958*3.1415926*sqrt(($lat2-$lat)*($lat2-$lat) + cos($lat2/57.29578)*cos($lat/57.29578)*($lon2-$lon)*($lon2-$lon))/180); $distancetotal = $distancecalc + $distancecalc1 +$distancecalc2; echo "$distancecalc&lt;br&gt; $distancecalc1&lt;br&gt; $distancecalc2&lt;br&gt;"; } echo "$distancetotal"; ?&gt; </code></pre> <p>I tried some things (mostly if... ) and also with more database requests, but I'm still having the problem of avoiding multiple calculations, and I also strongly believe there is way to code it to make it easier and clearer.</p> <p>I would appreciate some help on this one.</p> <p>Thank you very much.</p>
 

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