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copied!<p>Here is the method I cam up with in case it will help anyone.</p> <pre><code>// JavaScript Document var aInput = new Array(); aInput[0] = new Array("0", "1", "5"); aInput[1] = new Array("1", "1", "3"); aInput[2] = new Array("0", "10", "12"); aInput[3] = new Array("1", "10", "12"); var aOutput = []; console.log(ProcessArray(aInput)); function ProcessArray(aInput){ var input_indexed = [], elem = []; // elem holds the row to be added to the output // Get aInput[] into a more useful arrangement for (var i = 0; i < aInput.length; i++) { // if set is complete process it if (i > 0 && parseInt(aInput[i][0]) == 0 && parseInt(aInput[i-1][0]) > 0){ aOutput = aOutput.concat(calcOutput(elem, input_indexed)); // clear set elem = []; input_indexed =[]; } // if fist set is not there then create it input_indexed[parseInt(aInput[i][0])] = { start: parseInt(aInput[i][1]), end: parseInt(aInput[i][2]) }; // Initialize elem with the start value of each column elem.push(parseInt(aInput[i][1])); } // reset elem with the start value of each column aOutput = aOutput.concat(calcOutput(elem, input_indexed)); return aOutput; } function calcOutput(elem, input_indexed){ // Produce the output var aReturn = []; done = false; while (!done) { aReturn.push(elem.slice(0)); // push a copy of elem into result for (i = elem.length - 1;; i--) { // Increment elements from right to left if (i == -1) { // We've run out of columns done = true; break; } elem[i]++; // Increment the current column if (elem[i] <= input_indexed[i].end) { // If it doesn't overflow, we're done break; } // When it overflows, return to start value and loop around to next column elem[i] = input_indexed[i].start; } } return aReturn; } </code></pre>

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