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POPrint out dictionary in a table format?
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  1. POPrint out dictionary in a table format?
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    copied!<p>I have a dictionary that looks like:</p> <pre><code>band2 = {'channel11': [10812, 2162, 1972, 0], 'channel10': [10787, 2157, 1967, 0], 'channel3': [10612, 2122, 1932, 0], 'channel2': [10589, 2117, 1927, 0], 'channel1': [10564, 2112, 1922, 20], 'channel7': [10712, 2142, 1952, 26], 'channel6': [10687, 2137, 1947, 0], 'channel5': [10662, 2132, 1942, 32], 'channel4': [10637, 2127, 1937, 26], 'channel9': [10762, 2152, 1962, 0], 'channel8': [10737, 2147, 1957, 0], 'channel12': [10837, 2167, 1977, 15]} </code></pre> <p>I then sort it like so:</p> <pre><code>zipped = zip(*((key, value) for key, value in sorted(band2.items(), key= lambda x: int(x[0][7:])))) </code></pre> <p>This gives this result:</p> <pre><code>[('channel1', 'channel2', 'channel3', 'channel4', 'channel5', 'channel6', 'channel7', 'channel8', 'channel9', 'channel10', 'channel11', 'channel12'), ([10564, 2112, 1922, 20], [10589, 2117, 1927, 0], [10612, 2122, 1932, 0], [10637, 2127, 1937, 26], [10662, 2132, 1942, 32], [10687, 2137, 1947, 0], [10712, 2142, 1952, 26], [10737, 2147, 1957, 0], [10762, 2152, 1962, 0], [10787, 2157, 1967, 0], [10812, 2162, 1972, 0], [10837, 2167, 1977, 15])] </code></pre> <p>I am wondering how do i print this out in a certain format:</p> <pre><code>Channel 1 Channel 2 ...... Channel 12 value[0] value[0] ........value[0] value[1]/value[2] value[1]/value[2].....value[1]/value[2] value[3] value[3]...........value[3] </code></pre> <p>So an example output would be:</p> <pre><code>Channel 1 Channel 2 &lt;other values&gt; Channel 12 10564 10589 &lt;other values&gt; 10837 2112/1922 2117/1927 &lt;other values&gt; 2167/1977 20 0 &lt;other values&gt; 15 </code></pre> <p>I'm unsure how to go about printing this in a neat table, would I use format?</p>
 

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