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copied!<p>The View and the ViewModel are both regular classes that get instantiated. This is done by calling the constructor as in any other class. So, as a simple answer to your question: Set a breakpoint in each constructor and see which one gets hit first.</p> <p>There is no general answer to your question because it depends on your architecture and use case. Often, some control is bound to a property of the ViewModel of it's parent, which changes at some point. At that point your View already exists and you have no idea how long the value to which the property has been set is existing already. In other cases, your View is created for a specific ViewModel and takes it as constructor parameter.</p> <p>The one way to make sure that the ViewModel exists before the View is to pass the ViewModel as a constructor parameter. The idea behind constructor parameters is to express: "This class needs existing instances of type xy to be created", which is what you are asking for. However, as you will set it as the Views <code>DataContext</code> in the constructor and as the <code>DataContext</code> can change after creation of the View, you cannot be sure that the View won't get a new ViewModel assigned after creation. Even worse, you will not be able to use your control in XAML anymore, because it doesn't have a default constructor anymore.</p> <p>According to your first question, it is not really clear why the ViewModel should exist prior to the View. If you need to read a resource value from your View and assign it to a property on your ViewModel, I would expect it to be the other way around? Or are you accessing the View in your ViewModel (don't!)? </p> <p>The question is, why you have to ask this question in the first place. There is something pretty wrong in your (or your bosses...) concept: View and ViewModel are two entities which should really work without knowing about each other. The idea is to build applications that could work perfectly without a single View existing by just getting/setting values on ViewModels and to have Views which would compile any run perfectly well without ViewModels, just without anything to show or do... If you try to hack this approach, you're better off not using MVVM at all.</p>

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