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copied!<p>You are looping through every img tag in this line and printing each one:</p> <pre><code>for link in soup.find_all('img'): print link.get('src') </code></pre> <p>However, you are not writing to the file in that loop, you are just writing <code>link.get('src')+'\n'</code> at the very end.</p> <p>This will only write what link is currently assigned to, which is simply the <strong>last</strong> img tag that you found in your loop above. That is why only one 'src' value will be written to the output file.</p> <p>You need to be writing each line to the file within your loop that goes through each of the img tags that you are interested in. You'll need to do a little bit of rearranging to do that:</p> <pre><code>from bs4 import BeautifulSoup soup = BeautifulSoup(open("youtube.htm")) file = open("parseddata.txt", "wb") for link in soup.find_all('img'): print link.get('src') file.write(link.get('src')+"\n") file.flush() file.close() </code></pre> <p>You should also remember to close the file as I have added in the last line of the above snippet.</p> <p>Edit: As per Hooked's comment below, here is what this snippet would look like if you use the <code>with</code> keyword. Using <code>with</code> will close the file automatically for you as soon as the indented block ends, so that you don't even have to think about it:</p> <pre><code>from bs4 import BeautifulSoup soup = BeautifulSoup(open("youtube.htm")) with open("parseddata.txt", "wb") as file: for link in soup.find_all('img'): print link.get('src') file.write(link.get('src')+"\n") </code></pre>

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