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copied!<p><strong>Edit</strong>: You've changed the code so that there is no <code>i</code> anymore, so that part of the answer below doesn't apply anymore. But what you've said about the code that you've presented is simply not credible in two different ways:</p> <ol> <li><p>You've said that <code>prev[1] = man_val;</code> followd by <code>alert(prev[1]);</code> shows <code>undefined</code>, but that's simply not true of the code you've shown.</p></li> <li><p>You've said that <code>prev.push</code> causes an error saying <code>push</code> is not a function, but in the code you've shown, <code>prev</code> is definitely an array, and arrays definitely have <code>push</code>.</p></li> </ol> <p>My guess is that you have something you haven't shown which is either shadowing <code>prev</code> or assigning a non-array to it. But as you haven't shown that code, what you say about the code simply doesn't jibe with the code.</p> <p>Hopefully the below is of some use in whatever your actual situation is.</p> <hr> <blockquote> <p><code>count += 1;</code></p> <p><code>prev[1] = man_val;</code></p> <p><code>alert(prev[i]);// Problem is here</code></p> </blockquote> <p>You're using <code>i</code> there, whereas in the line above you're using <code>1</code>. You haven't shown any code declaring or initializing <code>i</code>, so we have no idea what value it may have, but apparently it doesn't have the value <code>1</code>.</p> <p>If you really want to push to the array, the usual thing would be to use <code>push</code> or assign to <code>prev[prev.length]</code>. So you rcode could be:</p> <pre><code>prev.push(man_val); alert(prev[prev.length - 1]); </code></pre> <p>or</p> <pre><code>prev[prev.length] = man_val; // This will increment `prev.length` alert(prev[prev.length - 1]); // ...which is why we're using -1 here </code></pre> <p>But if you do have an <code>i</code> (and you must somewhere, or trying to read a value from it like that would cause a <code>ReferenceError</code>) and you want to be using it, you want to be consistent with how you use it. For instance:</p> <pre><code>prev[i++] = man_val; alert(prev[i - 1]); </code></pre> <p>I'm assuming <code>i</code> starts at <code>0</code> there.</p>

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