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    copied!<p>You are raising a negative number to the power of a non-inverse (i.e. 1/2, 0.5, 0.25, 0.333333, etc.) which results in a complex number. Like sqrt(-1) aka (-1)^(0.5)</p> <p>Additionally you could also be equating 0/0 in two of your lines of code.</p> <p>Use this code instead: (It takes the absolute value of your power's base (preventing negative values, thus preventing imaginary answers (complex numbers = NaN = -1.#IND)) It also prevents you from dividing by 0 if n == 0... in this event it adds 0.00001 to the denominator</p> <pre><code>for(int j=0; j&lt;=n; j++)//calculation for angles and output displayed to user { Xnew2 = -j*(Y+R1)/((n)+((0.00001)*(n==0)); //calculate x coordinate Ynew2 = Y*(pow(abs(1-(pow((Xnew2/X),2))),0.5)); if(abs(Ynew2) &lt;= R1) cout&lt;&lt;"\n("&lt;&lt;Xnew2&lt;&lt;", "&lt;&lt;Ynew2&lt;&lt;")"&lt;&lt;endl; } { Xnew3 = -j*(Y+R1)/((n)+((0.00001)*(n==0)); //calculate x coordinate Ynew3 = Y*(pow(abs(1-(pow((Xnew3/X),2))),0.5)); //calculate y coordinate if(abs(Ynew3) &lt;= R1) cout&lt;&lt;"\n("&lt;&lt;Xnew3&lt;&lt;", "&lt;&lt;Ynew3&lt;&lt;")"&lt;&lt;endl; //show x,y coordinates } </code></pre> <p>*In the future avoid taking roots of negative numbers (which is the same as raising a negative number to a non-inverse-fraction power), avoid taking a logarithm of a negative number, and avoid dividing by 0 these all produce NaN (-1.#IND)</p> <p><br><br></p> <p>This code may be better (it uses conditional values to make your power's base zero if it is ever less than zero to prevent imaginary answers):</p> <pre><code>for(int j=0; j&lt;=n; j++)//calculation for angles and output displayed to user { Xnew2 = -j*(Y+R1)/((n)+((0.00001)*(n==0)); //calculate x coordinate Ynew2 = Y*(pow(((1-(pow((Xnew2/X),2)))*((1-(pow((Xnew2/X),2)))&gt;(0))),0.5)); if(abs(Ynew2) &lt;= R1) cout&lt;&lt;"\n("&lt;&lt;Xnew2&lt;&lt;", "&lt;&lt;Ynew2&lt;&lt;")"&lt;&lt;endl; } { Xnew3 = -j*(Y+R1)/((n)+((0.00001)*(n==0)); //calculate x coordinate Ynew3 = Y*(pow(((1-(pow((Xnew3/X),2))))*((1-(pow((Xnew3/X),2))))&gt;(0))),0.5)); //calculate y coordinate if(abs(Ynew3) &lt;= R1) cout&lt;&lt;"\n("&lt;&lt;Xnew3&lt;&lt;", "&lt;&lt;Ynew3&lt;&lt;")"&lt;&lt;endl; //show x,y coordinates } </code></pre> <p><br><br> <strong>*<em></strong> I'd also like to point out what "Magtheridon96" mentioned in his answer. The code now makes sure n is not equal to zero otherwise you could be dividing by zero, although I think that would produce #INF not #IND... unless "-j</em>(Y+R1)" is also zero, then it will be 0/0 which will be #IND</p>
 

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