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POZepto's clone() function not working properly or not possible to use clone() in combination with find()?
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  1. POZepto's clone() function not working properly or not possible to use clone() in combination with find()?
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    copied!<p>I have a simple image-slider, the html looks like this: </p> <pre><code>&lt;ul id="gallery-slider"&gt; &lt;li class="slide-li" &gt; &lt;img src="img1.png" width="1024" height="590" alt="img1"&gt; &lt;/li&gt; &lt;li class="slide-li" &gt; &lt;img src="img2.png" width="1024" height="590" alt="img2"&gt; &lt;/li&gt; &lt;li class="slide-li" &gt; &lt;img src="img3.png" width="1024" height="590" alt="img3"&gt; &lt;/li&gt; ... &lt;/ul&gt; </code></pre> <p>Now I want to add some thumbs to it to have an overview of the images. I want to create the thumbs from the images in the slides. I am using Zepto and tried the following to get the images and create new ones:</p> <pre><code>//imageSlider is the image slider instance in use for (var i = 1; i &lt;= imageSlider.length; i++) { //find the image in li var img = $('#gallery-slider li').eq(i-1).find('img').clone().attr({'width': 268, 'height': 172}); //view cloned element in console console.log(img); ... //here the img var will get pushed into an array } </code></pre> <p>Now when you spit out the img var in the console, it shows empty objects. I think the problem is the find() function, because when I do this: </p> <pre><code>var img = $('#gallery-slider li').eq(i-1).clone(); </code></pre> <p>the img var is not empty – the console output shows the cloned li elements. Is this a bug or can I not use the clone() function in combination with find() ?</p> <p><strong>Edit:</strong> </p> <p>I also tried this:</p> <pre><code>var img = $('#gallery-slider li').eq(i-1).find('img'), thumb = img.clone(); </code></pre> <p>– same result.</p>
 

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