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POJava skydrive rest file uploading
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copied!<p>I tried uploading a file to skydrive with the rest api in java.</p> <p>Here is my code:</p> <pre><code> public void UploadFile(File upfile) { if (upload_loc == null) { getUploadLocation(); } HttpClient client = new DefaultHttpClient(); client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); HttpPost post = new HttpPost(upload_loc + "?" + "access_token=" + access_token); try { MultipartEntity mpEntity = new MultipartEntity(null,"A300x",null); ContentBody cbFile = new FileBody(upfile, "multipart/form-data"); mpEntity.addPart("file", cbFile); post.setEntity(mpEntity); System.out.println(post.toString()); HttpResponse response = client.execute(post); BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); String line2 = ""; while ((line2 = rd.readLine()) != null) { System.out.println(line2); } } catch (IOException ex) { Logger.getLogger(Onlab.class.getName()).log(Level.SEVERE, null, ex); } client.getConnectionManager().shutdown(); } </code></pre> <p>But when I try to run it, I get this error:</p> <pre><code>{ "error": { "code": "request_body_invalid", "message": "The request entity body for multipart form-data POST isn't valid. The expected format is:\u000d\u000a--[boundary]\u000d\u000aContent-Disposition: form-data; name=\"file\"; filename=\"[FileName]\"\u000d\u000aContent-Type: application/octet-stream\u000d\u000a[CR][LF]\u000d\u000a[file contents]\u000d\u000a--[boundary]--[CR][LF]" } } </code></pre> <p>My biggest problem is that I don't see the request itself. I couldn't find any usable toString method for that. I tried this forced boundary format, but I tried it with empty constructor too.</p> <p>My file is now a txt with some text, and I think the boundary is the main problem or I should be configuring some more parameters. When I see the variables in debugging mode everything looks the same as a guide in the msdn.</p> <p>I'm new in the rest world and if it possible I want to keep this apache lib with the simple to use HttpClient and HttpPost classes.</p> <p>Thanks in advance, and sorry for my english.</p> <p>EDIT: Ok, after a long sleep I decided to try the PUT method instead of POST. The code work fine with minimal changes:</p> <pre><code>public void UploadFile(File upfile) { if (upload_loc == null) { getUploadLocation(); } HttpClient client = new DefaultHttpClient(); client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); String fname=upfile.getName(); HttpPut put= new HttpPut(upload_loc +"/"+fname+ "?" + "access_token=" + access_token); try { FileEntity reqEntity=new FileEntity(upfile); put.setEntity(reqEntity); HttpResponse response = client.execute(put); BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); String line2 = ""; while ((line2 = rd.readLine()) != null) { System.out.println(line2); } } catch (IOException ex) { Logger.getLogger(Onlab.class.getName()).log(Level.SEVERE, null, ex); } client.getConnectionManager().shutdown(); } </code></pre> <p>But there is no answer for the first question yet.</p>

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