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copied!<p>First, the signature of your data() function:</p> <pre><code>bool data(struct *sampleData) </code></pre> <p>cannot possibly work, because the argument lacks a name. When you declare a function argument that you intent to actually access, it needs a name. So change it to something like:</p> <pre><code>bool data(struct sampleData *samples) </code></pre> <p>But in C++, you don't need to use <code>struct</code> at all actually. So this can simply become:</p> <pre><code>bool data(sampleData *samples) </code></pre> <hr> <p>Second, the <code>sampleData</code> struct is not known to data() at that point. So you should declare it before that:</p> <pre><code>struct sampleData { int N; int M; string sample_name; string speaker; }; bool data(sampleData *samples) { samples->N = 10; samples->M = 20; // etc. } </code></pre> <p>And finally, you need to create a variable of type <code>sampleData</code>. For example, in your main() function:</p> <pre><code>int main(int argc, char *argv[]) { sampleData samples; data(&samples); } </code></pre> <p>Note that you need to pass the address of the variable to the data() function, since it accepts a pointer.</p> <p>However, note that in C++ you can directly pass arguments by reference and don't need to "emulate" it with pointers. You can do this instead:</p> <pre><code>// Note that the argument is taken by reference (the "&" in front // of the argument name.) bool data(sampleData &samples) { samples.N = 10; samples.M = 20; // etc. } int main(int argc, char *argv[]) { sampleData samples; // No need to pass a pointer here, since data() takes the // passed argument by reference. data(samples); } </code></pre>

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