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copied!<p>If you really want to use a regular expression, this following pattern should work:</p> <pre><code>NSString *pattern = @"latlng:\\{lat:([0-9.]+),lng:([0-9.]+)\\}"; </code></pre> <p><code>[0-9.]+</code> matches one or more characters which are a digit or <code>.</code>, and the parentheses around it make it a "capture group", so that the part of the string that matches this part of the pattern is available using <code>rangeAtIndex:</code>.</p> <p>To verify this, I have added the exact input data from your question as a resource file "data.txt" to my test application, and loaded that data with</p> <pre><code>NSURL *url = [[NSBundle mainBundle] URLForResource:@"data.txt" withExtension:nil]; NSError *error; NSString *locationStr = [NSString stringWithContentsOfURL:url encoding:NSUTF8StringEncoding error:&error]; </code></pre> <p>and then parsed the string with the regular expression</p> <pre><code>NSString *pattern = @"latlng:\\{lat:([0-9.]+),lng:([0-9.]+)\\}"; NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:0 error:&error]; NSArray *matches = [regex matchesInString:locationStr options:0 range:NSMakeRange(0, [locationStr length])]; for (NSTextCheckingResult *match in matches) { NSString *lat = [locationStr substringWithRange:[match rangeAtIndex:1]]; NSString *lng = [locationStr substringWithRange:[match rangeAtIndex:2]]; NSLog(@"latidude = %@, longitude = %@", lat, lng); } </code></pre> <p><em>Output:</em></p> <pre><code>latidude = 21.747064, longitude = 72.169678 </code></pre>

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