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copied!<p>I guess you don't want simply the lexicographic order (the solution would be obvious).</p> <p>First, remove the ".java" part and split your string on the character "_".</p> <pre><code>int dotIndex = string.indexOf("."); String []parts = split.substring(0, dotIndex).split("_"); </code></pre> <p>You are interested in parts[1] and parts[2]. The first is easy, it's just a number.</p> <pre><code>int fileNumber = Integer.parseInt(parts[1]); </code></pre> <p>The second one is always of the form "VX" with X being a number. But this part may not exist (if it's the base version of the file). In which case we can say that version is 0.</p> <pre><code>int versionNumber = parts.length < 2 ? 0 : Integer.parseInt(parts[2].substring(1)); </code></pre> <p>Now you can compare based on these two numbers.</p> <p>To make things simple, build a class FileIdentifier based on this:</p> <pre><code>class FileIdentifier { int fileNumber; int versionNumber; } </code></pre> <p>Then a function that create a FileIdentifier from a file name, with logic based on what I explained earlier.</p> <pre><code>FileIdentifier getFileIdentifierFromFileName(String filename){ /* .... */ } </code></pre> <p>Then you make a comparator on String, in which you get the FileIdentifier for the two strings and compare upon FileIdentifier members.</p> <p>Then, to get the string with "the highest value", you simply put all your strings in a list, and use <code>Collections.sort</code>, providing the comparator.</p>

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