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copied!<p>An algorithm (example values <code>$min=-186</code> and <code>$max=+153</code> as limits):</p> <ol> <li><p>Take these two limits <code>$min</code>, <code>$max</code> and mark them if you wish</p></li> <li><p>Calculate the difference between <code>$max</code> and <code>$min</code>: <code>$diff = $max - $min</code><br> <code>153 - (-186) = 339</code></p></li> <li><p>Calculate 10th logarithm of the difference <code>$base10 = log($diff,10)</code> = 2,5302</p></li> <li><p>Round down: <code>$power = round($base10)</code> = 2.<br> This is your tenth power as base unit</p></li> <li><p>To calculate <code>$step</code> calculate this:<br> <code>$base_unit = 10^$power</code> = 100;<br> <code>$step = $base_unit / 2</code>; (if you want 2 ticks per one <code>$base_unit</code>).</p></li> <li><p>Calculate if <code>$min</code> is divisible by <code>$step</code>, if not take the nearest (round up) one<br> (in the case of <code>$step = 50</code> it is <code>$loop_start = -150</code>)</p></li> <li><p><code>for ($i=$loop_start; $i<=$max; $i++=$step){ // $i's are your ticks</code></p></li> <li><p>end</p></li> </ol> <p>I tested it in Excel and it gives quite nice results, you may want to increase its functionality, </p> <p>for example (in point 5) by calculating <code>$step</code> first from <code>$diff</code>,<br> say <code>$step = $diff / 4</code> and round <code>$step</code> in such way that <code>$base_unit</code> is divisible by <code>$step</code>; </p> <p>this will avoid such situations that you have between (101;201) four ticks with <code>$step=25</code> and you have 39 steps <code>$step=25</code> between 0 and 999.</p>

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