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copied!<p>Use peakiness-test. It's a method to find all the possible peak between two local minima, and measure the peakiness based on a formula. If the peakiness higher than a threshold, the peak is accepted.</p> <p>Source: <a href="http://www.cs.ucf.edu/courses/cap6411/cap5415/spring02/Lecture-9-h.pdf" rel="nofollow">UCF CV CAP5415 lecture 9 slides</a></p> <p>Below is my code:</p> <pre><code>public static List<int> PeakinessTest(int[] histogram, double peakinessThres) { int j=0; List<int> valleys = new List<int> (); //The start of the valley int vA = histogram[j]; int P = vA; //The end of the valley int vB = 0; //The width of the valley, default width is 1 int W = 1; //The sum of the pixels between vA and vB int N = 0; //The measure of the peaks peakiness double peakiness=0.0; int peak=0; bool l = false; try { while (j < 254) { l = false; vA = histogram[j]; P = vA; W = 1; N = vA; int i = j + 1; //To find the peak while (P < histogram[i]) { P = histogram[i]; W++; N += histogram[i]; i++; } //To find the border of the valley other side peak = i - 1; vB = histogram[i]; N += histogram[i]; i++; W++; l = true; while (vB >= histogram[i]) { vB = histogram[i]; W++; N += histogram[i]; i++; } //Calculate peakiness peakiness = (1 - (double)((vA + vB) / (2.0 * P))) * (1 - ((double)N / (double)(W * P))); if (peakiness > peakinessThres & !valleys.Contains(j)) { //peaks.Add(peak); valleys.Add(j); valleys.Add(i - 1); } j = i - 1; } } catch (Exception) { if (l) { vB = histogram[255]; peakiness = (1 - (double)((vA + vB) / (2.0 * P))) * (1 - ((double)N / (double)(W * P))); if (peakiness > peakinessThres) valleys.Add(255); //peaks.Add(255); return valleys; } } //if(!valleys.Contains(255)) // valleys.Add(255); return valleys; } </code></pre>

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