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copied!<p>How to slice a string:</p> <pre><code>word = 'these' print word[0] # it's similar to list indexing, starts at 0 </code></pre> <p>To get the letters in backwards order, use a negative number: <code>word[-1]</code> is the last letter; <code>word[-2]</code> is the second to last, etc.</p> <p><code>word[1:]</code> returns every letter from index 1 (the second letter) to the end. 'word[:5]<code>returns every letter up to index 5 (exclusive, letters 1, 2, 3, and 4). </code>words[1:5]` returns every letter from index 1 up to index 5 (letters 2, 3, and 4).</p> <p>Since you have multiple lines, you want to do <code>words += lines.split()</code> because </p> <pre><code>untranslated = open('english.txt','r') vowels = ('a', 'e', 'i', 'o', 'u') # I like using lists/tuples rather than strings # if you are just checking if something is in it newWords = [] for lines in untranslated: words += lines.split() # this fixes the last line problem # this assumes each word is on one line, separated by a space (like: 'these are words') for word in words: # iterates through every word if word[0] in vowels: # if first letter is a vowel new_word = word + 'yay' else: new_word = word[1:] + word[0] + 'ay' newWords.apend(new_word) </code></pre> <p>Based off of Eric Roper's suggestion, you can create a dictionary as a translation:</p> <pre><code>newWords = {} for word in words: if word[0] in vowels: new_word = word + 'yay' newWords[word] = new_word else: new_word = word[1:] + word[0] + 'ay' newWords[word] = new_word </code></pre> <p>Some references:</p> <ul> <li><a href="http://www.tutorialspoint.com/python/python_strings.htm" rel="nofollow">Strings</a></li> <li><a href="http://www.tutorialspoint.com/python/python_dictionary.htm" rel="nofollow">Dictionaries</a></li> </ul>

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