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POC++ Any faster method to write a large binary file?
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  1. POC++ Any faster method to write a large binary file?
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    copied!<p><strong>Goal</strong></p> <p>My goal is to <em>quickly</em> create a file from a <em>large</em> binary string (a string that contains only 1 and 0).</p> <p><strong>Straight to the point</strong></p> <p>I need a function that can achieve my goal. If I am not clear enough, please read on.</p> <p><strong>Example</strong></p> <pre><code>Test.exe is running... . Inputted binary string: 1111111110101010 Writing to: c:\users\admin\desktop\Test.txt Done! File(Test.txt) In Byte(s): 0xFF, 0xAA . Test.exe executed successfully! </code></pre> <p><strong>Explanation</strong></p> <ul> <li>First, Test.exe requested the user to input a binary string.</li> <li>Then, it converted the inputted binary string to hexadecimal.</li> <li>Finally, it wrote the converted value to a file called Test.txt.</li> </ul> <p><strong>I've tried</strong></p> <p>As an fail attempt to achieve my goal, I've created this simple (and possibly horrible) function (hey, at least I tried):</p> <pre><code>void BinaryStrToFile( __in const char* Destination, __in std::string &amp;BinaryStr ) { std::ofstream OutputFile( Destination, std::ofstream::binary ); for( ::UINT Index1 = 0, Dec = 0; // 8-Bit binary. Index1 != BinaryStr.length( )/8; // Get the next set of binary value. // Write the decimal value as unsigned char to file. // Reset decimal value to 0. ++ Index1, OutputFile &lt;&lt; ( ::BYTE )Dec, Dec = 0 ) { // Convert the 8-bit binary to hexadecimal using the // positional notation method - this is how its done: // http://www.wikihow.com/Convert-from-Binary-to-Decimal for( ::UINT Index2 = 7, Inc = 1; Index2 + 1 != 0; -- Index2, Inc += Inc ) if( BinaryStr.substr( Index1 * 8, 8 )[ Index2 ] == '1' ) Dec += Inc; } OutputFile.close( ); }; </code></pre> <p><strong>Example of usage</strong></p> <pre><code>#include "Global.h" void BinaryStrToFile( __in const char* Destination, __in std::string &amp;BinaryStr ); int main( void ) { std::string Bin = ""; // Create a binary string that is a size of 9.53674 mb // Note: The creation of this string will take awhile. // However, I only start to calculate the speed of writing // and converting after it is done generating the string. // This string is just created for an example. std::cout &lt;&lt; "Generating...\n"; while( Bin.length( ) != 80000000 ) Bin += "10101010"; std::cout &lt;&lt; "Writing...\n"; BinaryStrToFile( "c:\\users\\admin\\desktop\\Test.txt", Bin ); std::cout &lt;&lt; "Done!\n"; #ifdef IS_DEBUGGING std::cout &lt;&lt; "Paused...\n"; ::getchar( ); #endif return( 0 ); }; </code></pre> <p><strong>Problem</strong></p> <p>Again, that was my fail attempt to achieve my goal. The problem is the speed. It is too slow. It took more than 7 minutes. Are there any method to quickly create a file from a large binary string?</p> <p>Thanks in advance,</p> <p>CLearner</p>
 

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