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copied!<p>I'm interpreting your code as follows. You have a <strong>struct</strong> named Vector with 3 members</p> <pre><code>struct Vector { double fieldA; double fieldB; double fieldC; } </code></pre> <p>The code below works as follows. It uses <code>std::find_if_not</code> with <strong>reverse iterators</strong> (<code>rbegin()</code> and <code>rend()</code>) to find the first element from the back that has a <code>fieldA</code> different from <code>0</code>. It then converts this to a regular iterator (using <code>base()</code>) and compares it to the end of the vector. Finally the call <code>v.erase</code> will actually erase them (the so-called <strong>erase-remove idiom</strong>)</p> <pre><code>#include <algorithm> #include <vector> #include <iostream> #include <iterator> int main() { struct Vector { int fieldA; int fieldB; }; std::vector<Vector> v = { Vector{ 1, 0 }, Vector{ 2, 1 }, Vector{ 0, 2 }, Vector{ 1, 3 }, Vector{ 0, 4 }, Vector{ 0, 5 }, Vector{ 5, 6 }, Vector{ 6, 7 }, Vector{ 0, 8 }, Vector{ 0, 9 }, Vector{ 0, 10} }; for (auto& e: v) { std::cout << "{" << e.fieldA << "," << e.fieldB << "}, "; }; std::cout << "\n"; auto m = std::find_if_not(v.rbegin(), v.rend(), [&](Vector const& elem){ return elem.fieldA == 0; }).base(); if (m != v.end()) // remove all but one matching element v.erase(m + 1, v.end()); for (auto& e: v) { std::cout << "{" << e.fieldA << "," << e.fieldB << "}, "; }; std::cout << "\n"; } </code></pre> <p>Output on <a href="http://liveworkspace.org/code/M8iTg%2414" rel="nofollow">LiveWorkSpace</a></p>

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