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copied!<blockquote> <p>the 4th decimal place is not considerd for the rounding</p> </blockquote> <p>This is not true. </p> <p>According to MSDN, <a href="http://msdn.microsoft.com/en-us/library/3s2d3xkk.aspx" rel="nofollow"><code>Math.Round(decimal)</code></a> uses a rounding type of <a href="http://msdn.microsoft.com/en-us/library/system.midpointrounding.aspx" rel="nofollow"><code>MidpointRounding.ToEven</code></a>. </p> <p>The Midpoint Rounding specifies the rounding behavior when the value to be rounded is exactly halfway between the two possible rounded values.</p> <p>For example, </p> <ul> <li><code>0.2649</code> will always round to <code>0.26</code></li> <li><code>0.2651</code> will always round to <code>0.27</code></li> </ul> <p>when rounding to two decimals.</p> <p>What's interesting is what happens in the case of <code>0.2650</code>: by default, using <code>MidpointRounding.ToEven</code> you get:</p> <ul> <li><strong><code>0.26</code></strong> for <code>Math.Round(0.2650, 2)</code></li> <li><code>0.28</code> for <code>Math.Round(0.2750, 2)</code></li> </ul> <p>That's because the rounding is done towards the even most significant digit after rounding (<code>6</code> in the first case, <code>8</code> in the second).</p> <p>If, however, you were to use <code>MidpointRounding.AwayFromZero</code>, you'd get:</p> <ul> <li><code>0.27</code> for <code>Math.Round(0.2650, 2, MidpointRounding.AwayFromZero)</code></li> <li><code>0.28</code> for <code>Math.Round(0.2750, 2, MidpointRounding.AwayFromZero)</code></li> </ul>

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