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copied!<p>A general solution is to wrap the array in a method that does implement <code>equals</code> (and <code>hashCode</code> and perhaps <code>compare</code>, possibly <code>toString</code> and other methods that might make sense) as you wish:</p> <pre><code>public final class IntArrayWrapper { private final IntArrayWrapper[] values; public IntArrayWrapper(int... values) { if (values == null) { throw new NullPointerException(); } this.values = values; } @Override public boolean equals(Object obj) { if (!(obj instanceof IntArrayWrapper)) { return false; } IntArrayWrapper other = (IntArrayWrapper)obj; return java.util.Arrays.equals(this.values, other.values); } @Override public int hashCode() { return java.util.Arrays.hashCode(values); } public int[] getValues() { return values; } [...] } </code></pre> <p>In this specific case, using arrays to contain certain fixed data values is poor design. Do it properly:</p> <pre><code>public final class Point { private final int x; private final int y; private final int z; public static Point of(int x, int y, int z) { return new Point(x, y, z); } private Point(int x, int y, int z) { this.x = x; this.y = y; this.z = z; } @Override public boolean equals(Object obj) { if (!(obj instanceof Point)) { return false; } Point other = (Point)obj; return this.x == other.x && this.y == other.y && this.z == other.z; } @Override public int hashCode() { int hash; hash = x; hash = hash*41+y; hash = hash*41+z; return hash; } [...] } </code></pre>

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