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copied!<p>Between <code>int32</code> and <code>int32_t</code>, (and likewise between <code>int8</code> and <code>int8_t</code>) the difference is pretty simple: the C standard defines <code>int8_t</code> and <code>int32_t</code>, but does not define anything named <code>int8</code> or <code>int32</code> -- the latter (if they exist at all) is probably from some other header or library (most likely predates the addition of <code>int8_t</code> and <code>int32_t</code> in C99).</p> <p>Plain <code>int</code> is quite a bit different from the others. Where <code>int8_t</code> and <code>int32_t</code> each have a specified size, <code>int</code> can be any size >= 16 bits. At different times, both 16 bits and 32 bits have been reasonably common (and for a 64-bit implementation, it should probably be 64 bits).</p> <p>On the other hand, <code>int</code> is guaranteed to be present in every implementation of C, where <code>int8_t</code> and <code>int32_t</code> are not. It's probably open to question whether this matters to you though. If you use C on small embedded systems and/or older compilers, it may be a problem. If you use it primarily with a modern compiler on desktop/server machines, it probably won't be.</p> <p>Oops -- missed the part about <code>char</code>. You'd use <code>int8_t</code> instead of char if (and only if) you want an integer type guaranteed to be exactly 8 bits in size. If you want to store characters, you probably want to use <code>char</code> instead. Its size can vary (in terms of number of bits) but it's guaranteed to be exactly one byte. One slight oddity though: there's no guarantee about whether a plain <code>char</code> is signed or unsigned (and many compilers can make it either one, depending on a compile-time flag). If you need to ensure its being either signed or unsigned, you need to specify that explicitly.</p>

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