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POWhy my menu is not hierarchical?
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  1. POWhy my menu is not hierarchical?
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    copied!<p>I want to create a hierarchical menu. The function:</p> <pre><code>/* * Table has 3 fields: `ID`, `PARENTID` and `NAME` * `ID` is unique, `PARENTID` showing his parent node id. * This function will go through it and build unordered list and call itself when needed to build subitems. * $level argument used to define wich node's subitems to build. Default is 0 which is top level. */ function showMenu($level = 0) { $result = mysql_query("SELECT * FROM `menus` WHERE `submenu` = ".$level); echo "&lt;ul&gt;"; while ($node = mysql_fetch_array($result)) { echo "&lt;li&gt;".$node['name']; $hasChild = mysql_fetch_array(mysql_query("SELECT * FROM `menus` WHERE `submenu` = ".$node['id'])) != null; IF ($hasChild) { showMenu($node['id']); } echo "&lt;/li&gt;"; } echo "&lt;/ul&gt;"; } </code></pre> <p>I've found on a stackoverflow in a similar question.</p> <p>I have a table <code>menus</code>:</p> <pre><code>+----+----------------+---------+ | id | name | submenu | +----+----------------+---------+ | 1 | FIRST HEADER | NULL | | 2 | SECOND HEADER | NULL | | 3 | THIRD HEADER | NULL | | 4 | (fh) submenu 1 | 1 | | 5 | (fh) submenu 2 | 1 | | 6 | (fh) submenu 3 | 1 | | 7 | (sh) submenu 1 | 2 | | 8 | (sh) submenu 2 | 2 | | 9 | (th) submenu 1 | 3 | | 10 | item 1 | 4 | | 11 | item 2 | 4 | +----+----------------+---------+ </code></pre> <p>I used this function in script</p> <pre><code>showMenu(4); </code></pre> <p>and here is the result:</p> <pre><code>&lt;ul&gt;&lt;li&gt;item 1&lt;/li&gt;&lt;li&gt;item 2&lt;/li&gt;&lt;/ul&gt; </code></pre> <p>as u can see, there is no word about even a piece of hierarchy, just a couple of items in source. What possibly wrong in my code?</p>
 

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