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copied!<p>Here's the solution I came up with. It does exactly what I need, while displaying the coordinates that are found in their proper places.</p> <p><a href="http://pastehtml.com/view/cowibn4bs.html" rel="nofollow">http://pastehtml.com/view/cowibn4bs.html</a> to see the fruits of my labour.</p> <pre><code>if(n==0){ for(var i=0; i < data.length; i++) { var xs = 0; var xy = 0; xs = xPlot - data[i][0]; ys = yPlot - data[i][1]; xs = xs * xs; ys = ys * ys; distance = Math.sqrt(xs + ys); if (distance <= 25){ display2(data[i][0] + ", " + data[i][1] + " - " + alliance); } else if(distance <= 60){ display3(data[i][0] + ", " + data[i][1] + " - " + alliance); } else if(distance <= 150){ display4(data[i][0] + ", " + data[i][1] + " - " + alliance); } } } else if(n>0){ $('#msgs2').html(''); $('#msgs3').html(''); $('#msgs4').html(''); for(var i=0; i < data.length; i++) { a = []; for(var j=0; j < coords.length; j++) { var xs = 0; var ys = 0; xs = coords[j][1] - data[i][0]; ys = coords[j][2] - data[i][1]; xs = xs * xs; ys = ys * ys; distance = Math.sqrt(xs + ys); if (distance <= 25){ a[j] = 'g'; } else if (distance <= 60){ a[j] = 'b'; } else if (distance <= 150){ a[j] = 'r'; } else{ a[j] = 0; } } if($.inArray(0, a) > -1){ } else if($.inArray("g", a) > -1 && $.inArray("b", a) === -1){ if($.inArray("r", a) === -1){ display2(data[i][0] + ", " + data[i][1] + " - " + alliance); } } else if($.inArray("b", a) > -1 && $.inArray("r", a) === -1){ display3(data[i][0] + ", " + data[i][1] + " - " + alliance); } else if($.inArray("r", a) > -1){ display4(data[i][0] + ", " + data[i][1] + " - " + alliance); } } } n++; </code></pre>

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