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copied!<p>Instead of putting the occurance inside a circle as an item in an array, count the number of occurances in an array with the same length as the number of circles. I.e. instead of <code>[g,g,g,g,b,b,r,r,r,r,r,r,r]</code>, use <code>[4,2,7]</code>. That way you don't have to keep the array sorted when adding items, you just increment the correct item.</p> <p>That also makes it easy to sort the result on relevance. You can create a numeric value for the array by looking at it as a number with the base being the same as the number of data coordinates. I.e.:</p> <pre><code>var n = arr[0] * data.length * data.length + arr[1] * data.length + arr[2]; </code></pre> <p>With 10 data coordinates, the array <code>[4,2,7]</code> would get the value 427, making it easy to compare it to the array <code>[3,5,0]</code> that would get the value 350.</p> <p>You can calculate the arrays as:</p> <pre><code>for(var i=0; i < coords.length; i++) { var arr = [0, 0, 0]; for(var j=0; j < data.length; j++) { var xs = coords[i][1] - data[j][0]; var ys = coords[i][2] - data[j][1]; distance = Math.sqrt(xs * xs + ys * ys); if (distance <= 25) { arr[0]++; } else if (distance <= 60) { arr[1]++; } else if (distance <= 150) { arr[2]++; } } coords[i].arr = arr; coords[i].value = arr[0] * data.length * data.length + arr[1] * data.length + arr[2]; } </code></pre> <p>Now you can sort the coordinates on the values:</p> <pre><code>coords.sort(function(a, b){ return a.value - b.value; }); </code></pre>

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