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POHow can i understand Thread.interrupt()?
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copied!<p>There are two code block in java.</p> <p>Block One:</p> <pre><code>@Test public void test1() { System.out.println("interrupt:" + Thread.currentThread().isInterrupted()); Thread.currentThread().interrupt(); System.out.println("interrupt:" + Thread.currentThread().isInterrupted()); } </code></pre> <p>Output:</p> <pre><code>interrupt:false interrupt:true </code></pre> <p>Block Two:</p> <pre><code>@Test public void test2() throws InterruptedException { Thread thread = new Thread(new Runnable() { @Override public void run() { System.out.println("running..."); } }); thread.interrupt(); TimeUnit.SECONDS.sleep(2); System.out.println("interrupt:" + thread.isInterrupted()); thread.start(); TimeUnit.SECONDS.sleep(2); System.out.println("interrupt:" + thread.isInterrupted()); } </code></pre> <p>Output:</p> <pre><code>interrupt:false running... interrupt:false </code></pre> <p>So, my questions:</p> <ol> <li>Why block one print <code>interrupt:true</code> after invoke <code>interrupt()</code> but block two not?</li> <li>What will JVM do after invoke interrupt()?</li> </ol> <p>Thanks!</p> <p>PS:Block Three:</p> <pre><code>@Test public void test3() { Thread thread = new Thread(new Runnable() { @Override public void run() { System.out.println("running..."); } }); thread.interrupt(); System.out.println("interrupt:" + thread.isInterrupted()); // thread.start(); // // thread.interrupt(); // // // System.out.println("interrupt:" + thread.isInterrupted()); } </code></pre> <p>Also output : <code>interrupt:false</code></p>

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