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copied!<p>To my knowledge, there is no direct way to get the day of an event in the Calendar API. If the date format of your results is as it is in your parameters (<code>2012-12-24T00:00:00Z</code>), you can use string formatting in combination with the <code>datetime</code> module. Here, the <code>%A</code> is the string formatting parameter that returns the day of the week of the datetime object defined by running <code>strptime</code> on our string with the corresponding format:</p> <pre><code>In [1]: from datetime import datetime In [2]: s = '2012-12-24T00:00:00Z' In [3]: d = datetime.strptime(s, '%Y-%m-%dT%H:%M:%SZ') In [4]: '{0:%A}'.format(d) Out[4]: 'Monday' </code></pre> <p>And as a function:</p> <pre><code>In [8]: def createDayName(s): ...: d = datetime.strptime(s, '%Y-%m-%dT%H:%M:%SZ') ...: return '{0:%A}'.format(d) ...: In [9]: createDayName('2012-12-24T00:00:00Z') Out[9]: 'Monday' In [10]: createDayName('2012-12-30T23:59:59Z') Out[10]: 'Sunday' </code></pre> <p>Building on that, if you need to handle multi-day events, you can try something like this, where the main piece involves <code>timedelta</code> and iterating the number of days between the two events (note that this is a bit arbitrary, but will hopefully provide a useful example):</p> <pre><code>from datetime import datetime, timedelta # This structure will allow us to append to our dictionary without # there needing to be a key first (comes in handy) from collections import defaultdict def days_in_range(start, end, daysDict): # Convert your start/end dates start_d = datetime.strptime(start, '%Y-%m-%dT%H:%M:%SZ') end_d = datetime.strptime(end, '%Y-%m-%dT%H:%M:%SZ') # Now iterate over the days between those two dates, adding # an arbitrary value to the 'day' key of our dict for i in range((end_d - start_d).days + 1): day_name = '{0:%A}'.format(start_d + timedelta(days=i)) daysDict[day_name].append(i) return daysDict # Create your dictionary that will have a list as the default value daysDict = defaultdict(list) start = '2012-12-24T00:00:00Z' end = '2012-12-30T23:59:59Z' # I would probably reevaluate this part, but the reason for # passing the dictionary itself to the function is so that # it can better fit into situations where you have multiple events # (although a class structure may be well-suited for this, but # that may be overcomplicating things a bit :) ) daysDict = days_in_range(start, end, daysDict) for day, value in daysDict.iteritems(): print day, value </code></pre> <p>This prints the following (as dictionaries are inherently unordered, it may appear different for you):</p> <pre><code>Monday [0] Tuesday [1] Friday [4] Wednesday [2] Thursday [3] Sunday [6] Saturday [5] </code></pre>

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