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POJava read into byte array
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copied!<p>I have a .txt file consisting of 1's and 0's like so;</p> <pre><code>11111100000001010000000101110010 11111100000001100000000101110010 00000000101001100010000000100000 </code></pre> <p>I would like to be able to read 8 (1's and 0's) and put each 'byte' into a byte array. So a line would be 4 bytes;</p> <pre><code>11111100 00000101 00000001 01110010 --> 4 bytes, line 1 11111100 00000110 00000001 01110010 --> 8 bytes, line 2 00000000 10100110 00100000 00100000 --> total 12 bytes, line 3 ... and so on. </code></pre> <p>I believe I need to store the data in a binary file but I'm not sure how to do this. Any help is greatly appreciated.</p> <p>Edit 1:</p> <p>I would like to put 8 1's and 0's (11111100, 00000101) into a byte and store in a byte array so 11111100 would be the first byte in the array, 00000101 the second and so on. I hope this is clearer.</p> <p>Edit 2:</p> <pre><code>fileopen = new JFileChooser(System.getProperty("user.dir") + "/Example programs"); // open file from current directory filter = new FileNameExtensionFilter(".txt", "txt"); fileopen.addChoosableFileFilter(filter); if (fileopen.showOpenDialog(null)== JFileChooser.APPROVE_OPTION) { try { file = fileopen.getSelectedFile(); //create FileInputStream object FileInputStream fin = new FileInputStream(file); byte[] fileContent = new byte[(int)file.length()]; fin.read(fileContent); for(int i = 0; i < fileContent.length; i++) { System.out.println("bit " + i + "= " + fileContent[i]); } //create string from byte array String strFileContent = new String(fileContent); System.out.println("File content : "); System.out.println(strFileContent); } catch(FileNotFoundException e){} catch(IOException e){} } </code></pre>

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