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copied!<p>I tried to formulate my version of url. My requirement was to capture instances in a String where possible url can be cse.uom.ac.mu - noting that it is not preceded by http nor www</p> <pre><code>String regularExpression = "((((ht{2}ps?://)?)((w{3}\\.)?))?)[^.&&[a-zA-Z0-9]][a-zA-Z0-9.-]+[^.&&[a-zA-Z0-9]](\\.[a-zA-Z]{2,3})"; assertTrue("www.google.com".matches(regularExpression)); assertTrue("www.google.co.uk".matches(regularExpression)); assertTrue("http://www.google.com".matches(regularExpression)); assertTrue("http://www.google.co.uk".matches(regularExpression)); assertTrue("https://www.google.com".matches(regularExpression)); assertTrue("https://www.google.co.uk".matches(regularExpression)); assertTrue("google.com".matches(regularExpression)); assertTrue("google.co.uk".matches(regularExpression)); assertTrue("google.mu".matches(regularExpression)); assertTrue("mes.intnet.mu".matches(regularExpression)); assertTrue("cse.uom.ac.mu".matches(regularExpression)); //cannot contain 2 '.' after www assertFalse("www..dr.google".matches(regularExpression)); //cannot contain 2 '.' just before com assertFalse("www.dr.google..com".matches(regularExpression)); // to test case where url www must be followed with a '.' assertFalse("www:google.com".matches(regularExpression)); // to test case where url www must be followed with a '.' //assertFalse("http://wwwe.google.com".matches(regularExpression)); // to test case where www must be preceded with a '.' assertFalse("https://www@.google.com".matches(regularExpression)); </code></pre>

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