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copied!<p>Here is a recursive solution:</p> <pre><code>class Test { private static Object[][] createArray(int n, Object[] values) { Object[][] result = null; int m = values.length; if (n == 1) { result = new Object[m][1]; for (int i = 0; i < m; ++i) result[i][0] = values[i]; } else { Object[][] array = createArray(n - 1, values); int l = array.length; result = new Object[m * l][n]; for (int i1 = 0; i1 < m; ++i1) { for (int i2 = 0; i2 < l; ++i2) { int i = i1 * l + i2; for (int j = 0; j < n; ++j) result[i][j] = j == 0 ? values[i1] : array[i2][j - 1]; } } } return result; } private static void printArray(Object[][] array) { System.out.println("{"); for (int i = 0; i < array.length; ++i) { System.out.print(" {"); for (int j = 0; j < array[0].length; ++j) System.out.printf(" %s", array[i][j].toString()); System.out.println(" }"); } System.out.println("}"); } public static void main(String[] args) { Object[] values = {'a', 'b', 'c'}; for (int n = 1; n <= 3; ++n) { System.out.printf("n = %d:\n", n); Object[][] array = createArray(n, values); printArray(array); System.out.println(); } } } </code></pre> <p>Output:</p> <pre><code>n = 1: { { a } { b } { c } } n = 2: { { a a } { a b } { a c } { b a } { b b } { b c } { c a } { c b } { c c } } n = 3: { { a a a } { a a b } { a a c } { a b a } { a b b } { a b c } { a c a } { a c b } { a c c } { b a a } { b a b } { b a c } { b b a } { b b b } { b b c } { b c a } { b c b } { b c c } { c a a } { c a b } { c a c } { c b a } { c b b } { c b c } { c c a } { c c b } { c c c } } </code></pre>

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