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copied!<pre><code>int printList(struct listNode * Head){ struct listNode *current = Head; while (Head != NULL){ printf("%d \n", *current); current = current->next; } </code></pre> <p>You're pretty close. </p> <p>Take a look at the condition on your while loop - the reason your program crashes is that 'Head' is never updated, so the condition is always true. So the program just keeps setting 'current' equal to 'current->next' without stopping until you get to the end of your list, at which point 'current->next' is NULL and the program crashes. </p> <p>If you change your while loop to check whether 'current' is NULL instead of 'Head', it will stop when it reaches the end of the list and your program won't crash.</p> <p>EDIT: Adding some pointers on fixing the extra zeroes showing up the linked list.</p> <pre><code>struct listNode Head = {0, NULL}; </code></pre> <p>At the beginning of your program, you're creating a node in your linked list with the value 0. So you've always got at least one 0 no matter what your input is. You might consider initializing Head to NULL instead. If you do that, you'll have to check for that condition in your insertNode function.</p> <p>You're also getting some extra zeroes because you're checking your loop condition ('while(x > 0)') <em>before</em> you get the input that you use to make that decision ('scanf("%d", &x);'). You might want to consider changing that order by using a 'do...while' instead of 'while'. Take a look at <a href="http://www.cprogramming.com/tutorial/c/lesson3.html" rel="nofollow">http://www.cprogramming.com/tutorial/c/lesson3.html</a> for an explanation of 'do...while' with examples. </p>

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