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copied!<p>Try this: </p> <pre><code>while( n != 0 ) { reverse = reverse * 10; reverse = reverse + n%10; n = n/10; } </code></pre> <p>Logic is to get a single digit in each iteration starting from unit place, until all digits are encountered.</p> <p><code>n</code> is the input no. <code>reverse</code> is the variable where reverse of <code>n</code> is stored after <code>while</code> is finished.</p> <p><code>%</code> operator when used with 10, gives you the digit at unit place. <code>/</code> operator when used with 10, goves you all the digits except the digit at unit place.</p> <p>When <code>n = 7364</code> and <code>reverse = 0</code></p> <p>in 1st iteration, loop will look like:</p> <pre><code>while(7364 != 0) // true { reverse = 0 * 10; // reverse = 0 reverse = 0 + 7364%10 // reverse = 4 n = 7364/10 // n = 736 } </code></pre> <p>in 2nd iteration:</p> <pre><code>while(736 != 0) // true { reverse = 4 * 10; // reverse = 40 reverse = 40 + 736%10 // reverse = 46 n = 736/10 // n = 73 } </code></pre> <p>in 3rd iteration:</p> <pre><code>while(73 != 0) // true { reverse = 46 * 10; // reverse = 460 reverse = 460 + 73%10 // reverse = 463 n = 73/10 // n = 7 } </code></pre> <p>in 4th iteration:</p> <pre><code>while(7 != 0) // true { reverse = 463 * 10; // reverse = 4630 reverse = 4630 + 7%10 // reverse = 4637 n = 7/10 // n = 0 } </code></pre> <p>in 5th iteration:</p> <pre><code>while(0 != 0) // false and loop ends { ... } </code></pre> <p>and we have <code>reverse = 4637</code>.</p>

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