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copied!<p>Python3 no longer supports print as a special form with the arguments following the print keyword (like <code>print x</code> in Python 2.x). Instead <code>print</code> is now a function and requires an argument list like in: <code>print(x)</code>. See "Print is a function" in <a href="http://docs.python.org/release/3.0.1/whatsnew/3.0.html" rel="nofollow">http://docs.python.org/release/3.0.1/whatsnew/3.0.html</a></p> <p>In addition the <code>break</code> statement cannot occur outside of a loop. Other than the C <code>switch</code> statement, <code>if</code> does not support break. As there is no fall-through logic for if-statements it is not requred. In order to stop execution of the function and return to the caller use <code>return</code>.</p> <p>Instead of the <code>is</code> operator, use the equality operator <code>==</code>. <code>is</code> tests if objects are identical, this is a stricter test than equality. More details can be found <a href="http://docs.python.org/reference/datamodel.html#object.__hash__" rel="nofollow">here</a>.</p> <p>In addition you are getting the weight as a string. You might want to convert the string to an integer for comparison with other integer values, using the function <code>int(weight)</code>.</p> <p>Also there are a number of other small errors: </p> <ul> <li>You are assigning the user input for the weight to <code>e</code> while you try to use the undefined variable name <code>w</code> in the function call</li> <li>The first parameter in the function is called <code>texture</code> but you are using <code>textura</code> in the function body.</li> <li>You are using <code>peso</code> instead of <code>weight</code> in one instance</li> </ul> <p>Here is a (less offensive) rewrite with those errors eliminated:</p> <pre><code>def stuff(color, weight): color_txt = "Your stuff is " if color == "green": color_txt += "green as an apple" elif color == "blue": color_txt += "blue as the sky" elif color == "purple": color_txt += "purple as an eggplant" else: print("Invalid color!") return w = 0 # converting a string to an integer might # throw an exception if the input is invalid try: w = int(weight) except ValueError: print("Invalid weight!") return weight_txt = "" if w<20: weight_txt = " and weighs so few" elif 20 <= w <= 50: weight_txt = " and weighs mid" elif w > 50: weight_txt = " and weighs a lot" else: print("Invalid weight!") return color_txt + weight_txt c = input("Input color: ") w = input("Input weight: ") r = stuff(c, w) print(r) </code></pre>

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