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copied!<p>Well, yes and no. In Linux, at the <code>_start:</code> label, <code>argc</code> is at <code>[esp]</code> and <code>argv[0]</code> is at <code>[esp + 4]</code>. If your code works, this must also be true of Mac OSX. By doing <code>-e main</code> on the ld command line, essentially <code>main</code> is lying about its name. It isn't really a "C style main". This label is jumped to, not called. If <code>main</code> (or _main, for 'doze and Mac OSX) is called by "C startup code" (crt2.o), then there's a return address on the stack, so <code>argc</code> is at <code>[esp + 4]</code> and <code>argv[0]</code> is at <code>[esp + 8]</code>. Also, as Tim tells you at news:comp.lang.asm.x86 <code>argv</code> is a <code>**</code> - a "pointer to pointer" - so you also need the <code>mov ebx, [ebx]</code> (a "de-reference"). I'm pretty sure in Windows, our code is called regardless of what we name the entrypoint. Can you get it to work that way?</p> <p>EDIT: Well this has pretty much been beaten to death, and "solved"(?), but I got bored, too. This works in Linux, and "might" be portable.</p> <p><code></p> <pre>; prints its own name (possibly portable?) ; nasm -f elf32 myprog.asm ; nasm -f macho myprog.asm --prefix _ ; nasm -f win32 myprog.asm --prefix _ ; gcc -o myprog myprog.o(bj) (-m32 for 64-bit systems) global main extern printf section .data prog db `Program: %s \n`, 0 section .text main: mov eax, [esp + 8] mov eax, [eax] push eax push prog call printf add esp, 4 * 2 ret ;---------------------- </code></pre>

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