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POWhat is the equivalent of "ByteBuffer.flip" & "ByteBuffer.slice" in .NET?
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  1. POWhat is the equivalent of "ByteBuffer.flip" & "ByteBuffer.slice" in .NET?
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    copied!<p>I need to port code from Java to C#. In the Java code, the methods "ByteBuffer.flip()" and "ByteBuffer.slice" is used, and I don't know how to translate this.</p> <p>I've read this question (<a href="https://stackoverflow.com/questions/607587/an-equivalent-of-javax-nio-buffer-flip-in-c">An equivalent of javax.nio.Buffer.flip() in c#</a>), but although an answer is given, I cannot figure how to apply it. According to Tom Hawtin, I should "Set the limit to the current position and then set the position to zero" in the underlying array. I am unsure as of how to change these values. (If you could explain the underlying logic, it would help me a lot :)</p> <p>As for the ByteBuffer.slice, I have no clue on how to translate it.</p> <p>EDIT: If it can be clearer with the actual code, I'll post it:</p> <p>Java:</p> <pre><code>ByteBuffer buff; buff.putShort((short) 0); buff.put(customArray); buff.flip(); buff.putShort((short) 0); ByteBuffer b = buff.slice(); short size = (short) (customFunction(b) + 2); buff.putShort(0, size); buff.position(0).limit(size); </code></pre> <p>So far, my translation in C#.NET:</p> <pre><code>BinaryWriter b = new BinaryWriter(); //ByteBuffer buff; b.Write((short)0); // buff.putShort((short) 0); b.Write(paramStream.ToArray()); // buff.put(customArray); b.BaseStream.SetLength(b.BaseStream.Position); // buff.flip; (not sure) b.BaseStream.Position = 0; // buff.flip; too (not sure) b.Write((short)0); // buff.putShort((short) 0) ??? // ByteBuffer b = buff.slice(); // Not done but I can do it, short size = (short) (customFunction(b) + 2); ??? // How do I write at a particular position? ??? // buff.position(0).limit(size); I don't know how to do this </code></pre> <p>Thank you!</p> <p>EDIT: Changed <code>b.BaseStream.SetLength(b.BaseStream.Length);</code> to <code>b.BaseStream.SetLength(b.BaseStream.Position);</code>, based on the Java docs.</p>
 

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