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copied!<p>Answer by Adamski is a good one and describes the steps in an encoding operation when using the general encode method (that takes a byte buffer as one of the inputs)</p> <p>However, the method in question (in this discussion) is a variant of encode - <strong>encode(CharBuffer in)</strong>. This is a <strong>convenience method that implements the entire encoding operation</strong>. (Please see java docs reference in P.S.)</p> <p>As per the docs, <strong>This method should therefore not be invoked if an encoding operation is already in progress</strong> (which is what is happening in ZenBlender's code -- using static encoder/decoder in a multi threaded environment).</p> <p>Personally, I like to use <em>convenience</em> methods (over the more general encode/decode methods) as they take away the burden by performing all the steps under the covers. </p> <p>ZenBlender and Adamski have already suggested multiple ways options to safely do this in their comments. Listing them all here:</p> <ul> <li>Create a new encoder/decoder object when needed for each operation (not efficient as it could lead to a large number of objects). OR,</li> <li>Use a ThreadLocal to avoid creating new encoder/decoder for each operation. OR,</li> <li>Synchronize the entire encoding/decoding operation (this might not be preferred unless sacrificing some concurrency is ok for your program) </li> </ul> <p>P.S.</p> <p>java docs references:</p> <ol> <li>Encode (convenience) method: <a href="http://docs.oracle.com/javase/6/docs/api/java/nio/charset/CharsetEncoder.html#encode%28java.nio.CharBuffer%29">http://docs.oracle.com/javase/6/docs/api/java/nio/charset/CharsetEncoder.html#encode%28java.nio.CharBuffer%29</a></li> <li>General encode method: <a href="http://docs.oracle.com/javase/6/docs/api/java/nio/charset/CharsetEncoder.html#encode%28java.nio.CharBuffer,%20java.nio.ByteBuffer,%20boolean%29">http://docs.oracle.com/javase/6/docs/api/java/nio/charset/CharsetEncoder.html#encode%28java.nio.CharBuffer,%20java.nio.ByteBuffer,%20boolean%29</a></li> </ol>

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