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copied!<p>Looks like you got some recursion going on there. Recursive function calls will eventually exceed the stack since this is where function pointers are stored.</p> <p>So here is how it happens:</p> <ol> <li>fetch calls extract in the request.get callback</li> <li>extract calls push in the mongo.pages.find callback</li> <li>push calls fetch inside the while loop</li> </ol> <p>This cycle seems to repeat until you run out of stack.</p> <p>In your case the stack is running very low by the time you call <code>cheerio.load</code> which is why it runs out right then and there.</p> <p>Although you most likely want to examine if that is a bug or something you intended, in order to get the same effect in nodejs without using straight recursion is to use:</p> <p><code>process.nextTick(functionToCall)</code>.</p> <p>It will leave the enclosed function, which pops its pointer off the stack, but call the <code>functionToCall</code> on the next tick.</p> <p>You can try it in the noderepl: </p> <p><code>process.nextTick(function () { console.log('hello'); })</code></p> <p>will print 'hello' immediately.</p> <p>Its simliar to <code>setTimeout(functionToCall, 0)</code>, but to be preferred over it.</p> <p>Relating to your code you could replace <code>self.fetch(url)</code> with <code>process.nextTick(function () { self.fetch(url); })</code> and should no longer run out of stack.</p> <p>That being said, as mentioned above, it is more likely that there is a bug in your code, so look into that first.</p>

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