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POHow to setup Symfony2 Bundles independently with related Entities
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  1. POHow to setup Symfony2 Bundles independently with related Entities
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    copied!<p>I am trying to figure out a smart way to implement my bundles with following requirements:</p> <ol> <li>I have a Bundle with logic named <code>LogicABundle</code></li> <li>I have a Bundle with common things as design and Menus called <code>AppBundle</code></li> <li>I have another Bundle with logic <code>LogicBBundle</code> with some entities related to <code>LogicABundle</code> entities</li> </ol> <p>I know want to be able to "deploy" two applications from this setup:</p> <ol> <li>Application one uses the <code>LogicABundle</code> and <code>AppBundle</code></li> <li>The second one uses <code>LogicABundle</code>, <code>LogicBBundle</code> and <code>AppBundle</code></li> </ol> <p>The issue is, that for the second application I need to relate some Entities from <code>LogicABundle</code> to <code>LogicBBundle</code>, which causes the first "deploy" option to brake, if I just have an entity in <code>LogicABundle</code> pointing to <code>LogicBBundle</code>.</p> <p>Is there a smart solution to deploy these two different applications independently? Here is an example in order to make it easier to understand: namespace My\LogicABundle\Entity\Game;</p> <pre><code>use Doctrine\ORM\Mapping as ORM; /** * My\LogicABundle\Entity\Game * * @ORM\Entity * */ class Game { /** * @var integer $id * * @ORM\Column(name="id", type="integer") * @ORM\Id * @ORM\GeneratedValue(strategy="AUTO") */ private $id; /** * @var string $title * * @ORM\Column(name="title", type="string") */ private $title; /** * * @var Message * @ORM\ManyToOne(targetEntity="\My\LogicBBundle\Entity\Message", inversedBy="games") * @ORM\JoinColumn(name="messag_id", referencedColumnName="id", nullable=false) * @Assert\NotNull() */ private $message; } </code></pre> <p>I want to be able to use the Game class in my standalone application only with LogicABundle, and in my second application I need the game Entity with message relation.</p>
 

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