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    copied!<p>Use scanf in following way to read the student name:</p> <pre><code>scanf(" %[^\n]",studentlist[i].name); </code></pre> <p>The first space in the format specifier is important. It negates the newline from previous input. The format, by the way, instructs to read until a newline (\n) is encountered.</p> <p><strong>[Edit: Adding explanation on request]</strong></p> <p>The format specifier for accepting a string is <code>%s</code>. But it allows you to enter non-whitespace characters only. The alternative way is to specify the characters that are acceptable (or not acceptable, based on the scenario) within square brackets.</p> <p>Within square brackets, you can specify individual characters, or ranges, or combination of these. To specify characters to be excluded, precede with a caret (^) symbol.</p> <p>So, <code>%[a-z]</code> would mean any character between a and z (both included) will be accepted</p> <p>In your case, we need every character other than the newline to be accepted. So we come up with the specifier <code>%[^\n]</code></p> <p>You will get more info on these specifiers from the web. Here's one link for convenience: <a href="http://beej.us/guide/bgc/output/html/multipage/scanf.html" rel="nofollow noreferrer">http://beej.us/guide/bgc/output/html/multipage/scanf.html</a></p> <p>The space in the beginning actually 'consumes' any preceding white space left over from previous input. You can refer the answer here for a detailed explanation: <a href="https://stackoverflow.com/questions/6083045/scanf-n-skips-the-2nd-input-but-n-does-not-why">scanf: &quot;%[^\n]&quot; skips the 2nd input but &quot; %[^\n]&quot; does not. why?</a></p>
 

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