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copied!<p>That is because once you submitted the new comment it will acting as a form submit and it is not working as like AJAX.</p> <p>Easiest way is to use a separate php file to save comments and <a href="http://jquery.malsup.com/form/" rel="nofollow"><strong>jquery form</strong></a> plugin add this to <code><HEAD></code> tag in <strong>comment.php</strong></p> <pre><code><HEAD> <script src="http://malsup.github.com/jquery.form.js"></script> <script> // wait for the DOM to be loaded $(document).ready(function() { // bind 'myForm' and provide a simple callback function $('#myForm').ajaxForm(function() { location.reload(); }); }); </script> </HEAD> <?php $coms = mysql_query("select * from comments where id = '$id';",$db); if(!$coms) { echo "coms error ".mysql_error(); exit; } // debug if (mysql_num_rows($coms)>0){ // 55 while($databack44 = mysql_fetch_array($coms)){ // 55 echo '<div style="width:100%; float:left;">'.$databack44[comments].'</div>'; } } // 55 else { echo 'No Comments'; } ?> <form method="post" action="function.php" id="myForm"> <textarea name="comments"></textarea> <input type="submit" value="Add" class="button green"> <input type="hidden" name="id" value="<?=$id?>"> <input type="hidden" name="additem" value="1"> </form> </code></pre> <p><strong>function.php</strong></p> <pre><code>if ($_POST[additem] == '1'){ // AA $additem = mysql_query(" insert into comments ( id, user_id, comments ) VALUES ( '$id', '$user', '$comments' )",$db); if(!$additem) { echo "input error ".mysql_error(); exit; } // debug } // close AA </code></pre> <p><strong>jquery form plugin</strong> is disabling the standard form submit function and send form data as ajax variables to the given <strong>form action url</strong>.</p> <p>after sending data to the <strong>function.php</strong>, <strong>comment.php</strong> will be reloading by location.reload().</p> <p>Now you have the new comments Hope this helps </p>

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