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copied!<p>It would be better to see if suitsArray contains the string objectSuits, rather than using rangeOfString.</p> <pre><code>if ([suitsArray containsObject:objectSuits]); [resultObjectsArray addObject:object]; </code></pre> <p>After edit: I think I understand now. This method looks at each word in suitsArray, and if it finds any of them in objectSuits, then object is added to the resultObjectArray.</p> <pre><code> for (NSString *aWord in suitsArray) { if ([objectSuits rangeOfString:aWord].length == aWord.length) { [resultObjectArray addObject:objectSuits]; break; } } </code></pre> <p>Second Edit: After further thought, the above code has a flaw in the logic that may or may not be important -- because it uses rangeOfString it will find words inside other words. So, if objectSuits was "This wine goes well with cheesecake" and suitsArray contained the word cheese, it would find a match (I can't imagine a wine that would be good with cheese would be good with cheesecake). So, here is a better solution, I think, that breaks objectSuit up into individual words and puts them into a set. suitsArray is also converted to a set, so that we can use intersectsSet: to find if there are any common words.</p> <pre><code>NSCharacterSet *sepSet = [NSCharacterSet characterSetWithCharactersInString:@" ,.;"]; NSArray *words = [objectSuits componentsSeparatedByCharactersInSet:sepSet]; NSSet *objectSuitsWords = [NSSet setWithArray:words]; NSSet *suitsSet = [NSSet setWithArray:suitsArray]; BOOL ans = [suitsSet intersectsSet:objectSuitsWords]; </code></pre> <p>So, if ans is 1, then that object should be added to the results array. Notice that sepSet starts with a space and includes a comma, period, and semicolon. There might be other things you might want to include, but I think this should work in most cases.</p>

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