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POHow to timeout function in python, timeout less than a second
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  1. POHow to timeout function in python, timeout less than a second
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    copied!<h3>Specification of the problem:</h3> <p>I'm searching through really great amount of lines of a log file and I'm distributing those lines to groups in order to regular expressions(RegExses) I have stored using the <code>re.match()</code> function. Unfortunately some of my RegExses are too complicated and Python sometimes gets himself to backtracking hell. Due to this I need to protect it with some kind of timeout. </p> <h3>Problems:</h3> <ul> <li><code>re.match</code>, I'm using, is Python's function and as I found out somewhere here on StackOverflow <em>(I'm really sorry, I can not find the link now :-( )</em>. It is very difficult to interrupt thread with running Python's library. For this reason threads are out of the game.</li> <li>Because evaluating of <code>re.match</code> function takes relatively short time and I want to analyse with this function great amount of lines, I need some timeout function that wont't take too long to execute <em>(this makes threads even less suitable, it takes really long time to initialise new thread)</em> and <strong>can be set to less than one second</strong>.<br> For those reasons, answers here - <a href="https://stackoverflow.com/questions/492519/timeout-on-a-python-function-call">Timeout on a function call</a> and here - <a href="https://stackoverflow.com/questions/2281850/timeout-function-if-it-takes-too-long-to-finish">Timeout function if it takes too long to finish</a> with decorator (alarm - 1sec and more) are off the table. </li> </ul> <p>I've spent this morning searching for solution to this question but I did not find any satisfactory answer.</p>
 

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