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POabout split command in string using vb.net
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copied!<p>am having url .it contain the querstring value like this.to split the url and store the querystring values in an array .query string values are not passed with in application . it comes from another application</p> <pre><code>url ---- http://.....?lead_id=152818&vendor_id=100001&list_id=1001&gmt_offset_now=0.00&phone_code=91&phone_number=9942321400&title=MR&first_name=Hari&middle_initial=Q&last_name=PUBLIC&address1=249+MUNDON+ROAD&address2=MALDON&address3=FL&city=44&state=TN&province=NO_PROVINCE&postal_code=600004&country_code=IN&gender=M&date_of_birth=0000-00-00&alt_phone=9942321400&email=test@test.com&security_phrase=nothing&comments=COMMENTS&user=22222&pass=test&campaign=OUTBOUND&phone_login=22222&original_phone_login=22222&phone_pass=test&fronter=22222&closer=22222&group=OUTBOUND&channel_group=OUTBOUND&SQLdate=2012-08-07+164931&epoch=1344338372&uniqueid=1344338352.12754&customer_zap_channel=&customer_server_ip=&server_ip=10.103.200.177&SIPexten=22222&session_id=8600062&phone=9942321400&parked_by=152818&dispo=N&dialed_number=9942321400&dialed_label=MAIN&source_id=10001&rank=1&owner=Southeast&camp_script=&in_script=&script_width=600&script_height=340&fullname=J.Hariharan&recording_filename=OUTBOUND_20120807-164911_22222_9942321400&recording_id=248601&user_custom_one=&user_custom_two=&user_custom_three=&user_custom_four=&user_custom_five=&preset_number_a=&preset_number_b=&preset_number_c=&preset_number_d=&preset_number_e=&preset_dtmf_a=&preset_dtmf_b=&session_name=1344338181_2222216466857" my question is i want to store the querystring values in an one dimensional string array. my code ------- Dim strarr() As String Dim s As String = "http://...../test.aspx?lead_id=152818&vendor_id=100001&list_id=1001&gmt_offset_now=0.00&phone_code=91&phone_number=9942321400&title=MR&first_name=Hari&middle_initial=Q&last_name=PUBLIC&address1=249+MUNDON+ROAD&address2=MALDON&address3=FL&city=44&state=TN&province=NO_PROVINCE&postal_code=600004&country_code=IN&gender=M&date_of_birth=0000-00-00&alt_phone=9942321400&email=test@test.com&security_phrase=nothing&comments=COMMENTS&user=22222&pass=test&campaign=OUTBOUND&phone_login=22222&original_phone_login=22222&phone_pass=test&fronter=22222&closer=22222&group=OUTBOUND&channel_group=OUTBOUND&SQLdate=2012-08-07+164931&epoch=1344338372&uniqueid=1344338352.12754&customer_zap_channel=&customer_server_ip=&server_ip=10.103.200.177&SIPexten=22222&session_id=8600062&phone=9942321400&parked_by=152818&dispo=N&dialed_number=9942321400&dialed_label=MAIN&source_id=10001&rank=1&owner=Southeast&camp_script=&in_script=&script_width=600&script_height=340&fullname=J.Hariharan&recording_filename=OUTBOUND_20120807-164911_22222_9942321400&recording_id=248601&user_custom_one=&user_custom_two=&user_custom_three=&user_custom_four=&user_custom_five=&preset_number_a=&preset_number_b=&preset_number_c=&preset_number_d=&preset_number_e=&preset_dtmf_a=&preset_dtmf_b=&session_name=1344338181_2222216466857" strarr = s.Split("?") Dim s1 As String = strarr(1) Dim constr() As String constr = s1.Split("&") but am not get correct result my result --------- list_id=1001 gmt_offset_now=0.00 phone_code=91 phone_number=9942321400 expected result --------------- 1001 0.00 91 9942321400 </code></pre>

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