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copied!<p>If you don't think there will be backwards unmatched parens (i.e. ")(") you can do this:</p> <pre><code>with open("myFile.txt","r") as readfile, open("outFile.txt","w") as outfile: for line in readfile: if line.count("(") != line.count(")") or line.count('"') % 2 != 0: outfile.write(line) </code></pre> <p>Otherwise you will have to count them one at a time to check for mismatches, like this:</p> <pre><code>with open("myFile.txt","r") as readfile, open("outFile.txt","w") as outfile: for line in readfile: count = 0 for char in line: if char == ")": count -= 1 elif char == "(": count += 1 if count < 0: break if count != 0 or text.count('"') % 2 != 0: outfile.write(line) </code></pre> <p>I can't think of any better way to handle it. Python doesn't support recursive regular expressions, so a regular expression solution is right out.</p> <p>One more thing about this: Given your data, it might be better to put that into a function and split your strings, which is easy to do with a regex, like this:</p> <pre><code>import re splitre = re.compile(".*?=(.*?)(?:(?=\s*?\S*?=)|(?=\s*$))") with open("myFile.txt","r") as readfile, open("outFile.txt","w") as outfile: for line in readfile: def matchParens(text): count = 0 for char in text: if char == ")": count -= 1 elif char == "(": count += 1 if count < 0: break return count != 0 or text.count('"') % 2 != 0 if any(matchParens(text) for text in splitre.findall(line)): outfile.write(line) </code></pre> <p>The reason why that might be better is that it checks each value pair individually, that way if you have an open paren in one value pair and a close paren in a later one, it won't think that there are no unbalanced parens.</p>

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