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copied!<p>It looks like you're hosting your page in <a href="http://dreamhost.com" rel="nofollow">dreamhost.com</a>, a hosting provider.</p> <p>When you set up your account, they probably gave you the chance to create email accounts ending with your domain (<em>yaddayadda@addisonbean.com</em>)</p> <p>You may want to create one, get the information: host where the SMTP (the "mail server") is located, username, password... And you'll have to fill all that in your script.</p> <p>I would recommend you start testing with another regular account (Gmail.com, <strike>Hotmail</strike> Outlook.com) and that you read (quite a bit) about what an SMTP server is (which is the server you'll have to talk to in order to have your email sent)</p> <p>Here's a simple script that should send emails using a gmail account. Fill the information that is shown with asterisks with your data, see if it works:</p> <pre><code>#!/usr/bin/env python import traceback from smtplib import SMTP from email.MIMEText import MIMEText smtpHost = "smtp.gmail.com" smtpPort = 587 smtpUsername = "***@gmail.com" smtpPassword = "***" sender = "***@gmail.com" def sendEmail(to, subject, content): retval = 1 if not(hasattr(to, "__iter__")): to = [to] destination = to text_subtype = 'plain' try: msg = MIMEText(content, text_subtype) msg['Subject'] = subject msg['From'] = sender # some SMTP servers will do this automatically, not all conn = SMTP(host=smtpHost, port=smtpPort) conn.set_debuglevel(True) #conn.login(smtpUsername, smtpPassword) try: if smtpUsername is not False: conn.ehlo() if smtpPort != 25: conn.starttls() conn.ehlo() if smtpUsername and smtpPassword: conn.login(smtpUsername, smtpPassword) else: print("::sendEmail > Skipping authentication information because smtpUsername: %s, smtpPassword: %s" % (smtpUsername, smtpPassword)) conn.sendmail(sender, destination, msg.as_string()) retval = 0 except Exception, e: print("::sendEmail > Got %s %s. Showing traceback:\n%s" % (type(e), e, traceback.format_exc())) retval = 1 finally: conn.close() except Exception, e: print("::sendEmail > Got %s %s. Showing traceback:\n%s" % (type(e), e, traceback.format_exc())) retval = 1 return retval if __name__ == "__main__": sendEmail("***@gmail.com", "Subject: Test", "This is a simple test") </code></pre> <p>Once you have the equivalent information for your domain (<em>smtpHost, smtpPort, smtpUsername...</em>) it MAY work as well (depends on the port they're using, it may be 25, which is the default for non-encrypted connections... or not... You'll have to check with <em>dreamhost.com</em> for that) </p> <p>Be aware that (since you're using a hosting that probably shares its SMTP server with other people) your "sender" may be <em>yaddayadda@addisonbean.com</em> but the actual information to connect to the <em>dreamhost.com</em> SMTP servers may be different: I'm guessing the '<code>smtpUsername</code>' may be the username you use to login in your site admin, the '<code>smtpHost</code>' may change to something like <code>smtp.dreamhost.com</code> or such... That I don't really know.</p> <p>You have a <a href="https://www.google.com/search?q=python%20smtplib%20example&ie=utf-8&oe=utf-8&client=ubuntu&channel=fs" rel="nofollow">lot of resources</a> on how to do that. </p> <p>You also seem to be a designer or photographer... One of those <strike>dudes</strike> people concern on how things look on the screen and all... Then you may wanna investigate what <a href="http://en.wikipedia.org/wiki/MIME" rel="nofollow">MiME emails</a> are. You know... so the email is not sent with text only, but you can put fancy HTML in it... <em>You know what I'm sayin'?</em></p>

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