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POgetting back into c++, void function with pointers, how to make get function
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  1. POgetting back into c++, void function with pointers, how to make get function
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    copied!<p>I have a project I'm working on that's actually a school project that I did successfully a long time ago. I haven't done C++ in a while, and I'm having a bit of a problem jumping back into it, especially with pointers. My question is, if I need a get and set function like this</p> <pre><code> class Student { private: char firstName[64]; char lastName[64]; public: void setName(char *fName, char *lName); void getName(char *fName, char *lName); } void Student::setName(char *fName, char *lName); { firstName = *fName; lastName = *lName; } </code></pre> <p>when try to make my getName function, I seem to be very confused as to how I'm supposed to return the names with the function returning void. I know that it doesn't really have to return it, if it sets a value to something that can be returned, but I guess i'm rusty enough with pointers that I can't seem to make this work. I've tried things that I think can't work, such as returning values, but i'm not sure what would go in this get function. </p> <pre><code> void Student::getName(char *fName, char *lName); { } int main() { char myFirstName[64] = "John" char myLastName[64] = "Doe" //testing to see if it's reading the char arrays correctly. cout &lt;&lt; "Your Name is:" &lt;&lt; myFirstName &lt;&lt; " " &lt;&lt; myLastName &lt;&lt; endl; Student aStudent; aStudent.setName(myFirstName, myLastName); //This part is where i'm confused. and i'm sure some above is confusing as well. getStudent = aStudent.getName(); } </code></pre> <p>I thought maybe I could return the private variable via the constructor, but why would I need a get function then? I'm just redoing this old assignment to get back into c++, I've been doing more network admin stuff, and ignored this for long enough to lose my mind apparently. Thanks in advance, and let me know if you need more information, I tried to be thorough.</p>
 

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