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copied!<p>As far as I understand, it's a property for references set to true when using references with <code>strict mode</code> in ECMAScript 5 (aka ES5) initialized. When <code>strict mode</code> is set, more operations will lead to errors (syntax, reference, for example initializing a variable without the <code>var</code> keyword). See the <a href="https://developer-new.mozilla.org/en-US/docs/JavaScript/Reference/Functions_and_function_scope/Strict_mode?redirectlocale=en-US&redirectslug=JavaScript/Strict_mode" rel="nofollow">MDN-documentation</a> for more on <code>strict mode</code>.</p> <p>[<strong>edit</strong>] based on comment I think it's for the scope where <code>strict mode</code> is defined. So in</p> <pre><code>function strict() { 'use strict'; // from here on and within the function // IsStrictReference is true showme = "Am I defined?"; return "Hi! I'm a strict mode function! " + showme; } function nonstrict() { // IsStrictReference is ... well, undefined I suppose, or false by default showme2 = "Am I defined?"; return "Hi! I'm NOT a strict mode function! " + showme2; } strict(); //=> ReferenceError: showme is not defined notstrict(); //=> "Hi! I'm NOT a strict mode function! Am I defined?" </code></pre> <p>Executing <code>strict()</code> throws a <code>ReferenceError</code>, but <code>nonstrict()</code> doesn't. If you had placed the <code>use strict</code>-statement outside the function blocks, executing both functions would throw a <code>ReferenceError</code>.</p>

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