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    copied!<p>Hey guys I thought for a long time and finally I have code for my problem, i am posting it here so that other can get benefit from this ....</p> <pre><code> public static string RemoveIncompleteTags(string source, string tag) { source = source.Replace(" ", " "); source = source.Replace("/n", string.Empty).Replace("/r", string.Empty).Replace("/t", string.Empty); source = source.Replace("&lt;" + tag + "&gt;&lt;/" + tag + "&gt;", string.Empty); source = source.Replace("&lt;" + tag + "&gt; &lt;/" + tag + "&gt;", string.Empty); source = source.Replace("&lt;" + tag + "&gt; &lt;/" + tag + "&gt;", string.Empty); Dictionary&lt;int, string&gt; oDict = new Dictionary&lt;int, string&gt;(); string[] souceList; Dictionary&lt;int, string&gt; final = new Dictionary&lt;int, string&gt;(); bool opening = false; bool operate = false; source = source.Replace(" ", " "); source = source.Replace("&gt;", "&gt; ").Replace("&lt;", " &lt;"); source = source.Replace(" &gt;", "&gt;").Replace("&lt; ", "&lt;"); source = source.Replace(" ", " ").Replace(" ", " "); souceList = source.Split(' '); for (int i = 0; i &lt; souceList.Length; i++) { string word = souceList[i]; if (word.ToLower() == "&lt;" + tag.ToLower() + "&gt;") { opening = true; operate = true; } else if (word.ToLower() == "&lt;/" + tag.ToLower() + "&gt;") { opening = false; operate = true; } if (operate) { if (opening) { oDict.Add(i, word); final.Add(i, word); } else { if (oDict.Count != 0) { oDict.Remove(oDict.Last().Key);//.ToList().RemoveAt(oDict.Count - 1); final.Add(i, word); } else { // need not to add to the output string // code if you want to log } } operate = false; opening = false; } else { final.Add(i, word); } } if (final.Count &gt; 0) { if (oDict.Count &gt; 0) { foreach (var key in oDict.Keys) { final.Remove(key); } } StringBuilder fText = new StringBuilder(); final.ToList().ForEach(wd =&gt; { if (wd.Value.Trim().Length &gt; 0) fText.Append(wd.Value.Trim() + " "); }); return fText.ToString().Trim(); } else { return string.Empty; } } </code></pre> <p>thanks...</p>
 

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